6(k-2)-8=4k-(3k-1)

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Solution for 6(k-2)-8=4k-(3k-1) equation: 



6(k-2)-8=4k-(3k-1)

We move all terms to the left:

6(k-2)-8-(4k-(3k-1))=0

We multiply parentheses

6k-(4k-(3k-1))-12-8=0



We calculate terms in parentheses: -(4k-(3k-1)), so:

4k-(3k-1)

We get rid of parentheses

4k-3k+1

We add all the numbers together, and all the variables

k+1

Back to the equation:

-(k+1)



We add all the numbers together, and all the variables

6k-(k+1)-20=0

We get rid of parentheses

6k-k-1-20=0

We add all the numbers together, and all the variables

5k-21=0

We move all terms containing k to the left, all other terms to the right

5k=21

k=21/5

k=4+1/5

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