5a-9=3(a+1)+19a+6

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Solution for 5a-9=3(a+1)+19a+6 equation: 



5a-9=3(a+1)+19a+6

We move all terms to the left:

5a-9-(3(a+1)+19a+6)=0



We calculate terms in parentheses: -(3(a+1)+19a+6), so:

3(a+1)+19a+6

We add all the numbers together, and all the variables

19a+3(a+1)+6

We multiply parentheses

19a+3a+3+6

We add all the numbers together, and all the variables

22a+9

Back to the equation:

-(22a+9)



We get rid of parentheses

5a-22a-9-9=0

We add all the numbers together, and all the variables

-17a-18=0

We move all terms containing a to the left, all other terms to the right

-17a=18

a=18/-17

a=-1+1/17

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