6(k+2)+1=136(k+2)+1=13

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Solution for 6(k+2)+1=136(k+2)+1=13 equation: 



6(k+2)+1=136(k+2)+1=13

We move all terms to the left:

6(k+2)+1-(136(k+2)+1)=0

We multiply parentheses

6k-(136(k+2)+1)+12+1=0



We calculate terms in parentheses: -(136(k+2)+1), so:

136(k+2)+1

We multiply parentheses

136k+272+1

We add all the numbers together, and all the variables

136k+273

Back to the equation:

-(136k+273)



We add all the numbers together, and all the variables

6k-(136k+273)+13=0

We get rid of parentheses

6k-136k-273+13=0

We add all the numbers together, and all the variables

-130k-260=0

We move all terms containing k to the left, all other terms to the right

-130k=260

k=260/-130

k=-2

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