3(y-4)+4y=9

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Solution for 3(y-4)+4y=9 equation: 



3(y-4)+4y=9

We move all terms to the left:

3(y-4)+4y-(9)=0

We add all the numbers together, and all the variables

4y+3(y-4)-9=0

We multiply parentheses

4y+3y-12-9=0

We add all the numbers together, and all the variables

7y-21=0

We move all terms containing y to the left, all other terms to the right

7y=21

y=21/7

y=3

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