6(k+2)+1=12

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Solution for 6(k+2)+1=12 equation: 



6(k+2)+1=12

We move all terms to the left:

6(k+2)+1-(12)=0

We add all the numbers together, and all the variables

6(k+2)-11=0

We multiply parentheses

6k+12-11=0

We add all the numbers together, and all the variables

6k+1=0

We move all terms containing k to the left, all other terms to the right

6k=-1

k=-1/6

k=-1/6

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