6(j-7)+5(2j+3)=47

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Solution for 6(j-7)+5(2j+3)=47 equation: 



6(j-7)+5(2j+3)=47

We move all terms to the left:

6(j-7)+5(2j+3)-(47)=0

We multiply parentheses

6j+10j-42+15-47=0

We add all the numbers together, and all the variables

16j-74=0

We move all terms containing j to the left, all other terms to the right

16j=74

j=74/16

j=4+5/8

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