2(b+3)-4(-2+b)=19

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Solution for 2(b+3)-4(-2+b)=19 equation: 



2(b+3)-4(-2+b)=19

We move all terms to the left:

2(b+3)-4(-2+b)-(19)=0

We add all the numbers together, and all the variables

2(b+3)-4(b-2)-19=0

We multiply parentheses

2b-4b+6+8-19=0

We add all the numbers together, and all the variables

-2b-5=0

We move all terms containing b to the left, all other terms to the right

-2b=5

b=5/-2

b=-2+1/2

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