6(g+3)=2-(g+31)

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Solution for 6(g+3)=2-(g+31) equation: 



6(g+3)=2-(g+31)

We move all terms to the left:

6(g+3)-(2-(g+31))=0

We multiply parentheses

6g-(2-(g+31))+18=0



We calculate terms in parentheses: -(2-(g+31)), so:

2-(g+31)

determiningTheFunctionDomain
-(g+31)+2

We get rid of parentheses

-g-31+2

We add all the numbers together, and all the variables

-1g-29

Back to the equation:

-(-1g-29)



We get rid of parentheses

6g+1g+29+18=0

We add all the numbers together, and all the variables

7g+47=0

We move all terms containing g to the left, all other terms to the right

7g=-47

g=-47/7

g=-6+5/7

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