-(z+6)+3z+1)=-2(z+1)

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Solution for -(z+6)+3z+1)=-2(z+1) equation: 



-(z+6)+3z+1)=-2(z+1)

We move all terms to the left:

-(z+6)+3z+1)-(-2(z+1))=0

We add all the numbers together, and all the variables

3z-(z+6)-2(z+1))+1)-(=0

We get rid of parentheses

3z-z-2(z+1))+1)-(-6=0

We add all the numbers together, and all the variables

2z-2(z+1))+1)-(-6=0

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