6(d+2)+3=3-2(d-4)

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Solution for 6(d+2)+3=3-2(d-4) equation: 



6(d+2)+3=3-2(d-4)

We move all terms to the left:

6(d+2)+3-(3-2(d-4))=0

We multiply parentheses

6d-(3-2(d-4))+12+3=0



We calculate terms in parentheses: -(3-2(d-4)), so:

3-2(d-4)

determiningTheFunctionDomain
-2(d-4)+3

We multiply parentheses

-2d+8+3

We add all the numbers together, and all the variables

-2d+11

Back to the equation:

-(-2d+11)



We add all the numbers together, and all the variables

6d-(-2d+11)+15=0

We get rid of parentheses

6d+2d-11+15=0

We add all the numbers together, and all the variables

8d+4=0

We move all terms containing d to the left, all other terms to the right

8d=-4

d=-4/8

d=-1/2

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