(8x-4)*(2x-1)=36

Solution for (8x-4)*(2x-1)=36 equation:

(8x-4)(2x-1)=36

We move all terms to the left:

(8x-4)(2x-1)-(36)=0

We multiply parentheses ..

(+16x^2-8x-8x+4)-36=0

We get rid of parentheses

16x^2-8x-8x+4-36=0

We add all the numbers together, and all the variables

16x^2-16x-32=0

a = 16; b = -16; c = -32;
Δ = b2-4ac
Δ = -162-4·16·(-32)
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2304}=48$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-48}{2*16}=\frac{-32}{32}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+48}{2*16}=\frac{64}{32}
=2
$