(3+x)/6=(x-5)/3

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Solution for (3+x)/6=(x-5)/3 equation: 



(3+x)/6=(x-5)/3

We move all terms to the left:

(3+x)/6-((x-5)/3)=0

We add all the numbers together, and all the variables

(x+3)/6-((x-5)/3)=0

We calculate fractions


x/()+(-((x-5)*6)/()=0



We calculate terms in parentheses: +(-((x-5)*6)/(), so:

-((x-5)*6)/(

We multiply all the terms by the denominator


-((x-5)*6)



We calculate terms in parentheses: -((x-5)*6), so:

(x-5)*6

We multiply parentheses

6x-30

Back to the equation:

-(6x-30)



We get rid of parentheses

-6x+30

Back to the equation:

+(-6x+30)



We get rid of parentheses

x/()-6x+30=0

We multiply all the terms by the denominator


x-6x*()+30*()=0

We add all the numbers together, and all the variables

x-6x*()=0

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