6(b-4)=-9+3b

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Solution for 6(b-4)=-9+3b equation: 



6(b-4)=-9+3b

We move all terms to the left:

6(b-4)-(-9+3b)=0

We add all the numbers together, and all the variables

6(b-4)-(3b-9)=0

We multiply parentheses

6b-(3b-9)-24=0

We get rid of parentheses

6b-3b+9-24=0

We add all the numbers together, and all the variables

3b-15=0

We move all terms containing b to the left, all other terms to the right

3b=15

b=15/3

b=5

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