6(b-3)=12+3b

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Solution for 6(b-3)=12+3b equation: 



6(b-3)=12+3b

We move all terms to the left:

6(b-3)-(12+3b)=0

We add all the numbers together, and all the variables

6(b-3)-(3b+12)=0

We multiply parentheses

6b-(3b+12)-18=0

We get rid of parentheses

6b-3b-12-18=0

We add all the numbers together, and all the variables

3b-30=0

We move all terms containing b to the left, all other terms to the right

3b=30

b=30/3

b=10

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