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10x^2-53x=11
We move all terms to the left:
10x^2-53x-(11)=0
a = 10; b = -53; c = -11;
Δ = b2-4ac
Δ = -532-4·10·(-11)
Δ = 3249
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3249}=57$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-53)-57}{2*10}=\frac{-4}{20} =-1/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-53)+57}{2*10}=\frac{110}{20} =5+1/2 $
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