6(b-2)=2b-3

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Solution for 6(b-2)=2b-3 equation: 



6(b-2)=2b-3

We move all terms to the left:

6(b-2)-(2b-3)=0

We multiply parentheses

6b-(2b-3)-12=0

We get rid of parentheses

6b-2b+3-12=0

We add all the numbers together, and all the variables

4b-9=0

We move all terms containing b to the left, all other terms to the right

4b=9

b=9/4

b=2+1/4

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