6(a+4)=3(2a-5)+a

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Solution for 6(a+4)=3(2a-5)+a equation: 



6(a+4)=3(2a-5)+a

We move all terms to the left:

6(a+4)-(3(2a-5)+a)=0

We multiply parentheses

6a-(3(2a-5)+a)+24=0



We calculate terms in parentheses: -(3(2a-5)+a), so:

3(2a-5)+a

We add all the numbers together, and all the variables

a+3(2a-5)

We multiply parentheses

a+6a-15

We add all the numbers together, and all the variables

7a-15

Back to the equation:

-(7a-15)



We get rid of parentheses

6a-7a+15+24=0

We add all the numbers together, and all the variables

-1a+39=0

We move all terms containing a to the left, all other terms to the right

-a=-39

a=-39/-1

a=+39

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