2t+8+(1/2)t-t=11

Solution for 2t+8+(1/2)t-t=11 equation:

2t+8+(1/2)t-t=11

We move all terms to the left:

2t+8+(1/2)t-t-(11)=0


Domain of the equation: 2)t!=0

t!=0/1

t!=0

t∈R


We add all the numbers together, and all the variables

2t+(+1/2)t-t+8-11=0

We add all the numbers together, and all the variables

t+(+1/2)t-3=0

We multiply parentheses

t^2+t-3=0

a = 1; b = 1; c = -3;
Δ = b2-4ac
Δ = 12-4·1·(-3)
Δ = 13
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{13}}{2*1}=\frac{-1-\sqrt{13}}{2}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{13}}{2*1}=\frac{-1+\sqrt{13}}{2}
$