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-1/4x+5/6=9/2x
We move all terms to the left:
-1/4x+5/6-(9/2x)=0
Domain of the equation: 4x!=0
x!=0/4
x!=0
x∈R
Domain of the equation: 2x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
-1/4x-(+9/2x)+5/6=0
We get rid of parentheses
-1/4x-9/2x+5/6=0
We calculate fractions
80x^2/288x^2+(-72x)/288x^2+(-1296x)/288x^2=0
We multiply all the terms by the denominator
80x^2+(-72x)+(-1296x)=0
We get rid of parentheses
80x^2-72x-1296x=0
We add all the numbers together, and all the variables
80x^2-1368x=0
a = 80; b = -1368; c = 0;
Δ = b2-4ac
Δ = -13682-4·80·0
Δ = 1871424
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1871424}=1368$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1368)-1368}{2*80}=\frac{0}{160} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1368)+1368}{2*80}=\frac{2736}{160} =17+1/10 $
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