4x2-16x=16x-39

Solution for 4x2-16x=16x-39 equation:

4x^2-16x=16x-39

We move all terms to the left:

4x^2-16x-(16x-39)=0

We get rid of parentheses

4x^2-16x-16x+39=0

We add all the numbers together, and all the variables

4x^2-32x+39=0

a = 4; b = -32; c = +39;
Δ = b2-4ac
Δ = -322-4·4·39
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-32)-20}{2*4}=\frac{12}{8}
=1+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-32)+20}{2*4}=\frac{52}{8}
=6+1/2
$