6(a+3)=-4a+4(1+2a)

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Solution for 6(a+3)=-4a+4(1+2a) equation: 



6(a+3)=-4a+4(1+2a)

We move all terms to the left:

6(a+3)-(-4a+4(1+2a))=0

We add all the numbers together, and all the variables

6(a+3)-(-4a+4(2a+1))=0

We multiply parentheses

6a-(-4a+4(2a+1))+18=0



We calculate terms in parentheses: -(-4a+4(2a+1)), so:

-4a+4(2a+1)

We multiply parentheses

-4a+8a+4

We add all the numbers together, and all the variables

4a+4

Back to the equation:

-(4a+4)



We get rid of parentheses

6a-4a-4+18=0

We add all the numbers together, and all the variables

2a+14=0

We move all terms containing a to the left, all other terms to the right

2a=-14

a=-14/2

a=-7

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