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8p(2p-4)=30
We move all terms to the left:
8p(2p-4)-(30)=0
We multiply parentheses
16p^2-32p-30=0
a = 16; b = -32; c = -30;
Δ = b2-4ac
Δ = -322-4·16·(-30)
Δ = 2944
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2944}=\sqrt{64*46}=\sqrt{64}*\sqrt{46}=8\sqrt{46}$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-32)-8\sqrt{46}}{2*16}=\frac{32-8\sqrt{46}}{32} $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-32)+8\sqrt{46}}{2*16}=\frac{32+8\sqrt{46}}{32} $
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