6(a+3)-5(3a+2)=2(2a-9)

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Solution for 6(a+3)-5(3a+2)=2(2a-9) equation: 



6(a+3)-5(3a+2)=2(2a-9)

We move all terms to the left:

6(a+3)-5(3a+2)-(2(2a-9))=0

We multiply parentheses

6a-15a-(2(2a-9))+18-10=0



We calculate terms in parentheses: -(2(2a-9)), so:

2(2a-9)

We multiply parentheses

4a-18

Back to the equation:

-(4a-18)



We add all the numbers together, and all the variables

-9a-(4a-18)+8=0

We get rid of parentheses

-9a-4a+18+8=0

We add all the numbers together, and all the variables

-13a+26=0

We move all terms containing a to the left, all other terms to the right

-13a=-26

a=-26/-13

a=+2

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