13b-7b(6-4)+28=2

Solution for 13b-7b(6-4)+28=2 equation:

13b-7b(6-4)+28=2

We move all terms to the left:

13b-7b(6-4)+28-(2)=0

We add all the numbers together, and all the variables

13b-7b2+28-2=0

We add all the numbers together, and all the variables

-7b^2+13b+26=0

a = -7; b = 13; c = +26;
Δ = b2-4ac
Δ = 132-4·(-7)·26
Δ = 897
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-\sqrt{897}}{2*-7}=\frac{-13-\sqrt{897}}{-14}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+\sqrt{897}}{2*-7}=\frac{-13+\sqrt{897}}{-14}
$