6(a+3)-10=-2(-a-4)

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Solution for 6(a+3)-10=-2(-a-4) equation: 



6(a+3)-10=-2(-a-4)

We move all terms to the left:

6(a+3)-10-(-2(-a-4))=0

We add all the numbers together, and all the variables

6(a+3)-(-2(-1a-4))-10=0

We multiply parentheses

6a-(-2(-1a-4))+18-10=0



We calculate terms in parentheses: -(-2(-1a-4)), so:

-2(-1a-4)

We multiply parentheses

2a+8

Back to the equation:

-(2a+8)



We add all the numbers together, and all the variables

6a-(2a+8)+8=0

We get rid of parentheses

6a-2a-8+8=0

We add all the numbers together, and all the variables

4a=0

a=0/4

a=0

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