35=5(7b-5)-(6+2b)

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Solution for 35=5(7b-5)-(6+2b) equation: 



35=5(7b-5)-(6+2b)

We move all terms to the left:

35-(5(7b-5)-(6+2b))=0

We add all the numbers together, and all the variables

-(5(7b-5)-(2b+6))+35=0



We calculate terms in parentheses: -(5(7b-5)-(2b+6)), so:

5(7b-5)-(2b+6)

We multiply parentheses

35b-(2b+6)-25

We get rid of parentheses

35b-2b-6-25

We add all the numbers together, and all the variables

33b-31

Back to the equation:

-(33b-31)



We get rid of parentheses

-33b+31+35=0

We add all the numbers together, and all the variables

-33b+66=0

We move all terms containing b to the left, all other terms to the right

-33b=-66

b=-66/-33

b=+2

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