6(9z+5)-8(4z-2)=90

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Solution for 6(9z+5)-8(4z-2)=90 equation: 



6(9z+5)-8(4z-2)=90

We move all terms to the left:

6(9z+5)-8(4z-2)-(90)=0

We multiply parentheses

54z-32z+30+16-90=0

We add all the numbers together, and all the variables

22z-44=0

We move all terms containing z to the left, all other terms to the right

22z=44

z=44/22

z=2

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