42x2-41x-20=0

Solution for 42x2-41x-20=0 equation:

42x^2-41x-20=0

a = 42; b = -41; c = -20;
Δ = b2-4ac
Δ = -412-4·42·(-20)
Δ = 5041
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5041}=71$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-41)-71}{2*42}=\frac{-30}{84}
=-5/14
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-41)+71}{2*42}=\frac{112}{84}
=1+1/3
$