6(8b+2)=8(b-4)

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Solution for 6(8b+2)=8(b-4) equation: 



6(8b+2)=8(b-4)

We move all terms to the left:

6(8b+2)-(8(b-4))=0

We multiply parentheses

48b-(8(b-4))+12=0



We calculate terms in parentheses: -(8(b-4)), so:

8(b-4)

We multiply parentheses

8b-32

Back to the equation:

-(8b-32)



We get rid of parentheses

48b-8b+32+12=0

We add all the numbers together, and all the variables

40b+44=0

We move all terms containing b to the left, all other terms to the right

40b=-44

b=-44/40

b=-1+1/10

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