4(q+12)=20

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Solution for 4(q+12)=20 equation: 



4(q+12)=20

We move all terms to the left:

4(q+12)-(20)=0

We multiply parentheses

4q+48-20=0

We add all the numbers together, and all the variables

4q+28=0

We move all terms containing q to the left, all other terms to the right

4q=-28

q=-28/4

q=-7

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