11-42=5(z-5)

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Solution for 11-42=5(z-5) equation: 



11-42=5(z-5)

We move all terms to the left:

11-42-(5(z-5))=0

We add all the numbers together, and all the variables

-(5(z-5))-31=0



We calculate terms in parentheses: -(5(z-5)), so:

5(z-5)

We multiply parentheses

5z-25

Back to the equation:

-(5z-25)



We get rid of parentheses

-5z+25-31=0

We add all the numbers together, and all the variables

-5z-6=0

We move all terms containing z to the left, all other terms to the right

-5z=6

z=6/-5

z=-1+1/5

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