6(8-3x)2x+1)=107

Solution for 6(8-3x)2x+1)=107 equation:

6(8-3x)2x+1)=107

We move all terms to the left:

6(8-3x)2x+1)-(107)=0

We add all the numbers together, and all the variables

6(-3x+8)2x+1)-107=0

We add all the numbers together, and all the variables

6(-3x+8)2x=0

We multiply parentheses

-36x^2+96x=0

a = -36; b = 96; c = 0;
Δ = b2-4ac
Δ = 962-4·(-36)·0
Δ = 9216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9216}=96$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(96)-96}{2*-36}=\frac{-192}{-72}
=2+2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(96)+96}{2*-36}=\frac{0}{-72}
=0
$