2(x+3)-7=23-5(x+3x)

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Solution for 2(x+3)-7=23-5(x+3x) equation: 



2(x+3)-7=23-5(x+3x)

We move all terms to the left:

2(x+3)-7-(23-5(x+3x))=0

We add all the numbers together, and all the variables

2(x+3)-(23-5(+4x))-7=0

We multiply parentheses

2x-(23-5(+4x))+6-7=0



We calculate terms in parentheses: -(23-5(+4x)), so:

23-5(+4x)

determiningTheFunctionDomain
-5(+4x)+23

We multiply parentheses

-20x+23

Back to the equation:

-(-20x+23)



We add all the numbers together, and all the variables

2x-(-20x+23)-1=0

We get rid of parentheses

2x+20x-23-1=0

We add all the numbers together, and all the variables

22x-24=0

We move all terms containing x to the left, all other terms to the right

22x=24

x=24/22

x=1+1/11

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