6(7z+4)=27

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Solution for 6(7z+4)=27 equation: 



6(7z+4)=27

We move all terms to the left:

6(7z+4)-(27)=0

We multiply parentheses

42z+24-27=0

We add all the numbers together, and all the variables

42z-3=0

We move all terms containing z to the left, all other terms to the right

42z=3

z=3/42

z=1/14

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