(x-12)+(31x)=80

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Solution for (x-12)+(31x)=80 equation:



(x-12)+(31x)=80
We move all terms to the left:
(x-12)+(31x)-(80)=0
We add all the numbers together, and all the variables
31x+(x-12)-80=0
We get rid of parentheses
31x+x-12-80=0
We add all the numbers together, and all the variables
32x-92=0
We move all terms containing x to the left, all other terms to the right
32x=92
x=92/32
x=2+7/8

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