2(3-z)+z/2=-4

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Solution for 2(3-z)+z/2=-4 equation: 



2(3-z)+z/2=-4

We move all terms to the left:

2(3-z)+z/2-(-4)=0

We add all the numbers together, and all the variables

2(-1z+3)+z/2-(-4)=0

We add all the numbers together, and all the variables

2(-1z+3)+z/2+4=0

We multiply parentheses

-2z+z/2+6+4=0

We multiply all the terms by the denominator


-2z*2+z+6*2+4*2=0

We add all the numbers together, and all the variables

z-2z*2+20=0

Wy multiply elements

z-4z+20=0

We add all the numbers together, and all the variables

-3z+20=0

We move all terms containing z to the left, all other terms to the right

-3z=-20

z=-20/-3

z=6+2/3

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