6(6y+5)+19=3(4y-2)-15

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Solution for 6(6y+5)+19=3(4y-2)-15 equation: 



6(6y+5)+19=3(4y-2)-15

We move all terms to the left:

6(6y+5)+19-(3(4y-2)-15)=0

We multiply parentheses

36y-(3(4y-2)-15)+30+19=0



We calculate terms in parentheses: -(3(4y-2)-15), so:

3(4y-2)-15

We multiply parentheses

12y-6-15

We add all the numbers together, and all the variables

12y-21

Back to the equation:

-(12y-21)



We add all the numbers together, and all the variables

36y-(12y-21)+49=0

We get rid of parentheses

36y-12y+21+49=0

We add all the numbers together, and all the variables

24y+70=0

We move all terms containing y to the left, all other terms to the right

24y=-70

y=-70/24

y=-2+11/12

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