-3(2n-5)=1/2(-12n+38)

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Solution for -3(2n-5)=1/2(-12n+38) equation: 



-3(2n-5)=1/2(-12n+38)

We move all terms to the left:

-3(2n-5)-(1/2(-12n+38))=0



Domain of the equation: 2(-12n+38))!=0

n∈R



We multiply parentheses

-6n-(1/2(-12n+38))+15=0

We multiply all the terms by the denominator


-6n*2(-12n+38))-(1+15*2(-12n+38))=0

Wy multiply elements

-12n^2(-+30n(-=0

We use the square of the difference formula

-12n^2(-30n(-=0

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