6(5y-2)+5(2y+6)=25(3y+2)-11y

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Solution for 6(5y-2)+5(2y+6)=25(3y+2)-11y equation: 



6(5y-2)+5(2y+6)=25(3y+2)-11y

We move all terms to the left:

6(5y-2)+5(2y+6)-(25(3y+2)-11y)=0

We multiply parentheses

30y+10y-(25(3y+2)-11y)-12+30=0



We calculate terms in parentheses: -(25(3y+2)-11y), so:

25(3y+2)-11y

We add all the numbers together, and all the variables

-11y+25(3y+2)

We multiply parentheses

-11y+75y+50

We add all the numbers together, and all the variables

64y+50

Back to the equation:

-(64y+50)



We add all the numbers together, and all the variables

40y-(64y+50)+18=0

We get rid of parentheses

40y-64y-50+18=0

We add all the numbers together, and all the variables

-24y-32=0

We move all terms containing y to the left, all other terms to the right

-24y=32

y=32/-24

y=-1+1/3

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