15(x+3)=6(x-5)-5(x+4)-3

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Solution for 15(x+3)=6(x-5)-5(x+4)-3 equation: 



15(x+3)=6(x-5)-5(x+4)-3

We move all terms to the left:

15(x+3)-(6(x-5)-5(x+4)-3)=0

We multiply parentheses

15x-(6(x-5)-5(x+4)-3)+45=0



We calculate terms in parentheses: -(6(x-5)-5(x+4)-3), so:

6(x-5)-5(x+4)-3

We multiply parentheses

6x-5x-30-20-3

We add all the numbers together, and all the variables

x-53

Back to the equation:

-(x-53)



We get rid of parentheses

15x-x+53+45=0

We add all the numbers together, and all the variables

14x+98=0

We move all terms containing x to the left, all other terms to the right

14x=-98

x=-98/14

x=-7

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