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6(5x-5)=3(3x-5)
We move all terms to the left:
6(5x-5)-(3(3x-5))=0
We multiply parentheses
30x-(3(3x-5))-30=0
We calculate terms in parentheses: -(3(3x-5)), so:We get rid of parentheses
3(3x-5)
We multiply parentheses
9x-15
Back to the equation:
-(9x-15)
30x-9x+15-30=0
We add all the numbers together, and all the variables
21x-15=0
We move all terms containing x to the left, all other terms to the right
21x=15
x=15/21
x=5/7
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