b(b+3)=-12

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Solution for b(b+3)=-12 equation: 



b(b+3)=-12

We move all terms to the left:

b(b+3)-(-12)=0

We add all the numbers together, and all the variables

b(b+3)+12=0

We multiply parentheses

b^2+3b+12=0

a = 1; b = 3; c = +12;
Δ = b2-4ac
Δ = 32-4·1·12
Δ = -39
Delta is less than zero, so there is no solution for the equation

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