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6(5-2v)=-4(3v-1)
We move all terms to the left:
6(5-2v)-(-4(3v-1))=0
We add all the numbers together, and all the variables
6(-2v+5)-(-4(3v-1))=0
We multiply parentheses
-12v-(-4(3v-1))+30=0
We calculate terms in parentheses: -(-4(3v-1)), so:We get rid of parentheses
-4(3v-1)
We multiply parentheses
-12v+4
Back to the equation:
-(-12v+4)
-12v+12v-4+30=0
We add all the numbers together, and all the variables
26!=0
There is no solution for this equation
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