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3x(8x-3)=
We move all terms to the left:
3x(8x-3)-()=0
We add all the numbers together, and all the variables
3x(8x-3)=0
We multiply parentheses
24x^2-9x=0
a = 24; b = -9; c = 0;
Δ = b2-4ac
Δ = -92-4·24·0
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{81}=9$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-9}{2*24}=\frac{0}{48} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+9}{2*24}=\frac{18}{48} =3/8 $
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