6(4x+3)=6(2x+1)+12x+12

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Solution for 6(4x+3)=6(2x+1)+12x+12 equation: 



6(4x+3)=6(2x+1)+12x+12

We move all terms to the left:

6(4x+3)-(6(2x+1)+12x+12)=0

We multiply parentheses

24x-(6(2x+1)+12x+12)+18=0



We calculate terms in parentheses: -(6(2x+1)+12x+12), so:

6(2x+1)+12x+12

We add all the numbers together, and all the variables

12x+6(2x+1)+12

We multiply parentheses

12x+12x+6+12

We add all the numbers together, and all the variables

24x+18

Back to the equation:

-(24x+18)



We get rid of parentheses

24x-24x-18+18=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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