6(4-z)=-2z

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Solution for 6(4-z)=-2z equation: 



6(4-z)=-2z

We move all terms to the left:

6(4-z)-(-2z)=0

We add all the numbers together, and all the variables

6(-1z+4)-(-2z)=0

We multiply parentheses

-6z-(-2z)+24=0

We get rid of parentheses

-6z+2z+24=0

We add all the numbers together, and all the variables

-4z+24=0

We move all terms containing z to the left, all other terms to the right

-4z=-24

z=-24/-4

z=+6

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