2/5(y+5)-2=3/5(3-y)

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Solution for 2/5(y+5)-2=3/5(3-y) equation: 



2/5(y+5)-2=3/5(3-y)

We move all terms to the left:

2/5(y+5)-2-(3/5(3-y))=0



Domain of the equation: 5(y+5)!=0

y∈R





Domain of the equation: 5(3-y))!=0

y∈R



We add all the numbers together, and all the variables

2/5(y+5)-(3/5(-1y+3))-2=0

We calculate fractions


(10y(-)/(5(y+5)*5(-1y+3)))+(-15yy/(5(y+5)*5(-1y+3)))-2=0



We calculate terms in parentheses: +(10y(-)/(5(y+5)*5(-1y+3))), so:

10y(-)/(5(y+5)*5(-1y+3))

We add all the numbers together, and all the variables

10y0/(5(y+5)*5(-1y+3))

We multiply all the terms by the denominator


10y0

We add all the numbers together, and all the variables

10y

Back to the equation:

+(10y)





We calculate terms in parentheses: +(-15yy/(5(y+5)*5(-1y+3))), so:

-15yy/(5(y+5)*5(-1y+3))

We multiply all the terms by the denominator


-15yy

Back to the equation:

+(-15yy)



We get rid of parentheses

10y-15yy-2=0

We move all terms containing y to the left, all other terms to the right

10y-15yy=2

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