6(4-3x)=2(22-8x)-3(2+3x)

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Solution for 6(4-3x)=2(22-8x)-3(2+3x) equation: 



6(4-3x)=2(22-8x)-3(2+3x)

We move all terms to the left:

6(4-3x)-(2(22-8x)-3(2+3x))=0

We add all the numbers together, and all the variables

6(-3x+4)-(2(-8x+22)-3(3x+2))=0

We multiply parentheses

-18x-(2(-8x+22)-3(3x+2))+24=0



We calculate terms in parentheses: -(2(-8x+22)-3(3x+2)), so:

2(-8x+22)-3(3x+2)

We multiply parentheses

-16x-9x+44-6

We add all the numbers together, and all the variables

-25x+38

Back to the equation:

-(-25x+38)



We get rid of parentheses

-18x+25x-38+24=0

We add all the numbers together, and all the variables

7x-14=0

We move all terms containing x to the left, all other terms to the right

7x=14

x=14/7

x=2

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