4(2x+1)=3(x+12)

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Solution for 4(2x+1)=3(x+12) equation: 



4(2x+1)=3(x+12)

We move all terms to the left:

4(2x+1)-(3(x+12))=0

We multiply parentheses

8x-(3(x+12))+4=0



We calculate terms in parentheses: -(3(x+12)), so:

3(x+12)

We multiply parentheses

3x+36

Back to the equation:

-(3x+36)



We get rid of parentheses

8x-3x-36+4=0

We add all the numbers together, and all the variables

5x-32=0

We move all terms containing x to the left, all other terms to the right

5x=32

x=32/5

x=6+2/5

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