((y+6)/4)+((y-3)/5)=5y-4

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Solution for ((y+6)/4)+((y-3)/5)=5y-4 equation: 



((y+6)/4)+((y-3)/5)=5y-4

We move all terms to the left:

((y+6)/4)+((y-3)/5)-(5y-4)=0

We get rid of parentheses

((y+6)/4)+((y-3)/5)-5y+4=0

We calculate fractions


-5y+(5y+30)/()+(4y-12)/()+4=0

We multiply all the terms by the denominator


-5y*()+(5y+30)+(4y-12)+4*()=0

We add all the numbers together, and all the variables

-5y*()+(5y+30)+(4y-12)=0

We get rid of parentheses

-5y*()+5y+4y+30-12=0

We add all the numbers together, and all the variables

9y-5y*()+18=0

We move all terms containing y to the left, all other terms to the right

9y-5y*()=-18

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